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-0.2x^2+1.2x+8=0
a = -0.2; b = 1.2; c = +8;
Δ = b2-4ac
Δ = 1.22-4·(-0.2)·8
Δ = 7.84
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.2)-\sqrt{7.84}}{2*-0.2}=\frac{-1.2-\sqrt{7.84}}{-0.4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.2)+\sqrt{7.84}}{2*-0.2}=\frac{-1.2+\sqrt{7.84}}{-0.4} $
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